Returning From A Nested Function In Javascript

I'm trying to make a function that uses jquery's ajaxfunction to get some info from my ajax.php file. code: function ajaxIt(dataLine){ $.ajax({ type: 'POST', ur

Solution 1:

You need to invoke a callback function to process data that way:

functionajaxIt(dataLine, cb){
    $.ajax({
        type: "POST",
        url: "ajax.php",
        data: "ajax=true&"+dataLine,
        success: function(msg){                
            if($.isFunction(cb))
               cb.apply(null, [msg]);
        }
    });
}

ajaxIt("action=loggedIn", function(data){
      if(data === "1"){
         console.log("Logged In");
         loggedIn=true;
         initiate2();
      }
});

Solution 2:

$.ajax is asynchronous. This means that it will return right away, instead of waiting for the AJAX query to execute and retrieve a result from the server. By the time the message from the server arrives, your ajaxIt function has already finished working.

What you should use here is a continuation-passing style. Provide ajaxIt with a continuation: a function that explains what should be done once ajaxIt has finished working.

functionajaxIt(data, continuation) {
  data.ajax = true;
  $.post("ajax;php", data, function(msg) {
    console.log("[AjaxIt]: returned "+msg);
    continuation(msg);
  }); 
}

ajaxIt({action:"logged-in"}, function(result) {
  if (result == "1") {
    console.log("Logged In");
    loggedIn=true;
    initiate2();
  }
});