Sort Javascript Array By Numbers And Letters

I want to sort this javascript array: [103,3,4,6,8,'8L',67,1,11,19,68,86,107,'9L']; sort it by numbers and letters, so the result will look like this: [1,3,4,6,8,'8L','9L',11,19

Solution 1:

You can do this easily using array .sort() & localeCompare() method by passing the {numeric: true} option like:

var unordered = [103,3,4,6,8,"8L",67,1,11,19,68,86,107,"9L"];
var correct = unordered.sort((a,b) => 
  a.toString().localeCompare(b.toString(), undefined, {numeric: true}))
console.log( correct )

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Solution 2:

It looks like you'll want to start by treating everything in your sort function like a string. Then split the numbers from the rest of the string and test them separately. Something like this:

const ordered = unordered.sort(function(a, b) {
  // Break apart the assumed strings (Numbers then everything else)const [, aNumber, aString] = `${a}`.match(/(\d*)(.*)/);
  const [, bNumber, bString] = `${b}`.match(/(\d*)(.*)/);

  // Test numbersif(Number(aNumber) < Number(bNumber)) return -1;
  if(Number(aNumber) > Number(bNumber)) return1;

  // Test letters if there is a tiereturn aString < bString ? -1 : 1;
});