Javascript - Get Indices Of True Values In A Boolean Array

Let's say I have an array with the following values - var arr = [true, true, false, false, false, true, false]; I'm looking for logic which will give me the following output - [0,

Solution 1:

You can use .reduce() to do this in one pass:

const arr = [true, true, false, false, false, true, false]
const indices = arr.reduce(
  (out, bool, index) => bool ? out.concat(index) : out, 
  []
)
console.log(indices)

You start by passing an empty array [] as the initialValue to .reduce() and use a ternary ? operator to determine whether to .concat() the index or not.

---

Alternatively, you can use the more recent .flatMap() method:

const arr = [true, true, false, false, false, true, false]
const indices = arr.flatMap((bool, index) => bool ? index : [])
console.log(indices)

If your browser does not yet support it, you'll get an Uncaught TypeError: arr.flatMap is not a function. In that case, you can use my polyfill definition from here.

Solution 2:

You could map the indices or for falsy values -1 and then filter all indices which are not -1.

var array = [true, true, false, false, false, true, false],
    result = array
        .map((b, i) => b ? i : -1)
        .filter(i => i !== -1);
        
console.log(result);

Solution 3:

A potentially more elegant solution is:

[...arr.keys()].filter(i => arr[i])

or alternatively

[...arr.entries()].filter(([, v]) => v).map(([i]) => i)

Solution 4:

You can simply use a loop and check the boolean value true in your if condition:

var arr = [true, true, false, false, false, true, false];
var indexArray = [];
arr.forEach((val, index) => {
  if(val){
    indexArray.push(index);
  }
});

console.log(indexArray);

Solution 5:

try this

var arr = [true, true, false, false, false, true, false];
var indexArray = [];
arr.forEach(function(value, index) {
    if (value) {
        indexArray.push(index);
    }
})
console.log(indexArray);