Determine If All Letters In A String Are In Alphabetical Order Javascript

I'm attempting to write a JavaScript function to determine if all letters in a string are in alphabetical order. The following would keep returning 'SyntaxError: Unexpected token d

Solution 1:

default is a keyword in JavaScript, and cannot be a variable name.

EDIT: Also, you have a logic issue: if you iterate up to length, in your last iteration you will check the last character against undefined; the test will fail, and you will return false. Rewrite into:

for(var i=0; i<s.length - 1; i++) {

EDIT2: I am not actually even sure why you're using that variable, since it has no bearing to the rest of your code. This should work as well (also, I moved the range from [0..length-1) to [1..length) for easier calculation):

functionorderedWords(str) {
    var s=str.toLowerCase().split("");
    for(var i=1; i<s.length; i++) {
        if (s[i - 1] > s[i]) {
            returnfalse;
        }
    }
    returntrue;
}

EDIT3: Simpler, shorter:

function orderedWords(str) {
    return str == str.split('').sort().join('');
}

Solution 2:

It looks like you're looking for more than a sort? With this function you can use any letter order defined in map, and also the function removes punctuation just in case you need to check messy strings.

var map = "abcdefghijklmnopqrstuvwxyz";

functionorderedWords(str,map){
    str = str.replace(/(.)(?=.*\1)/g, "");
    str = str.replace(/\W/g, '');
    var test = ""for(var i in map){
        if(str.indexOf(map[i])>-1){
            test += map[i];
        }
    }
    if(test.toLowerCase() == str.toLowerCase()){
        returntrue;
    }
    returnfalse;
}

console.log(orderedWords("aaabcdefffz", map));
console.log(orderedWords("abcdefzjjab", map));