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Match Two Quotes Not Preceded By Opening Bracket

I need a regex matching all occurrences of two quotes ('') not preceded by opening bracket ((). I did a negative lookahead for the bracket followed by a quote. But why is this not

Solution 1:

Here is a solution that will work correctly even in case you need to handle consecutive double apostrophes:

var output = "''(''test'''''''test".replace(/(\()?''/g, function($0, $1){
	return $1 ? $0 : 'x';
});
document.body.innerHTML = output;

Here, the /(\()?''/g regex searches for all matches with the ( and without, but inside the replace callback method, we check for the Group 1 match. If Group 1 matched, and is not empty, we use the whole match as the replacement text ($0 stands for the whole match value) and if it is not (there is no ( before '') we just insert the replacement.


Solution 2:

It's bad that Javascript doesn't support lookback but there is a workaround.

try:

[^\(]('{2,2})

See https://regex101.com/r/gT5jR6/1


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